Calculate `Delta_(r)G^(@)` and emf (E) that can be obtained from the following cell under the standard conditions at `25^(@)C? Zn(s)|Zn^(2+)(aq)||Sn^(2+)(aq)|Sn(s)`
`["Given : "E_(Zn^(2+)|Zn)^(@)=-0.76V , E_(Sn^(2+)|Sn)^(@)=-0.14V and F="96500 C.mol."^(-1)]`

Calculate Delta_(r)G^(@) and e.m.f. (E) that can be obtained from the following cell under the standard conditions at 25^(@)C: Zn(s)|Zn^(2+)(aq)" "Sn^(2+)(aq)|Sn(s) Given E_(Zn^(2+)//Zn)^(@)=-0.76V,E_(Sn^(2+)//Sn)^(@)=-0.14V And F=96500C" "mol^(-1) OR (a) Define conductivity and molar conductivity for the solution of an electrolyte. Discuss their variation with concentration. (b) Calculation the standard cell potential of the galvanic cell in which the following reaction takes place: Fe^(2+)(aq)+Ag^(+)(aq)toFe^(3+)(aq)+Ag(s) Calculate the Delta_(r)G^(@) and equilibrium constant of the reaction also. (E_(Ag^(+)//Ag)^(@)=0.80,E_(Fe^(3+)//Fe^(2+))^(@)=0.77V)

Calculate the maximum electrical work that can be obtained from the following cell under the standard conditions at 25^(@)C . Zn//Zn^(2+) (aq)"||"Fe^(2+)(aq)//Fe Given that E_(Zn^(2+)(aq)//Zn)^(Theta)= -0.76V E^(Theta)Fe^(2+) (aq)//Fe= -0.44 V and F = 96500"C mol"^(-1)

Calculate the standard Gibbs energy for the cell : Zn(s)|Zn^(2+)(aq)||Sn^(2+)(aq)|Sn(s) E_((Zn^(2+)//Zn))^(@)=-0.76V,E_((Sn^(2+)//Sn))^(@) = -0.16V , F=96500C .

Calculate the standard Gibbs energy for the cell : Zn(s)+Zn^(2+)(aq)||Cu^(2+)(aq)|Cu(s) E_((Zn^(2+)//Zn)^(@))=-0.76V,E_((Cu^(2+)//Cu))^(@)=0.34V , F=96500 C .

Calculate the standard Gibbs energy for the cell : Zn(s)|Zn^(2+)(aq)||Cd^(2+)(aq)|Cd(s) E_((Zn^(2+)//Zn))^(@)=-0.76V,E_((Cd^(2+)//Cd))^(@)=-0.403V,F=96500C .

Calculate the maximum work that can be obtained from the daniell call given below, Zn(s)|Zn^(2+)(aq)||Cu^(2+)(aq)|Cu(s) . Given that E_(Zn^(2+)//Zn)^(@)=-0.76V and E_(Cu^(2+)//Cu)^(@)=+0.34V .

Calculate the maximum work that can be obtained from the daniell call given below, Zn(s)|Zn^(2+)(aq)||Cu^(2+)(aq)|Cu(s) . Given that E_(Zn^(2+)//Zn)^(@)=-0.76V and E_(Cu^(2+)//Cu)^(@)=+0.34V .

Calculate cell potential of Fe|Fe^(2+)(a=0.6)||Sn^(2+)(a=0.2)|Sn Given : E_(Fe^(2+)|Fe)^(@)=-0.44V, E_(Sn^(2+)|Sn)^(@)=+0.14V