The co-efficient of thermal expansion of a rod is temperature dependent and is given by the formula `alpha = aT`, where `a` is a positive constant at T `"in"^(@)C`. if the length of the rod is l at temperature `0^(@)C`, then the temperature at which the length will be `2l` is

Does the co-efficient of linear expansion depend on the scale of temperature and unit of length?

The coefficient of linear expansion of a rod is alpha and its length is L. The increase in temperature required to increase its legnth by 1% is

A rod of length l and cross-section area A has a variable thermal conductivity given by K = alpha T, where alpha is a positive constant and T is temperature in kelvin. Two ends of the rod are maintained at temperature T_(1) and T_(2) (T_(1)gtT_(2)) . Heat current flowing through the rod will be

A rod of length l and cross-section area A has a variable thermal conductivity given by K = alpha T, where alpha is a positive constant and T is temperature in kelvin. Two ends of the rod are maintained at temperature T_(1) and T_(2) (T_(1)gtT_(2)) . Heat current flowing through the rod will be

A rod of length l and cross sectional area A has a variable conductivity given by K=alphaT , where alpha is a positive constant T is temperatures in Kelvin. Two ends of the rod are maintained at temperatures T_1 and T_2(T_1gtT_2) . Heat current flowing through the rod will be

A rod of length l and cross sectional area A has a variable conductivity given by K=alphaT , where alpha is a positive constant T is temperatures in Kelvin. Two ends of the rod are maintained at temperatures T_1 and T_2(T_1gtT_2) . Heat current flowing through the rod will be

The temperature gradient in a rod of 0.5 m length is 80^(@)C//m . It the temperature of hotter end of the rod is 30^(@)C , then the temperature of the cooler end is

The temperature gradient in a rod of 0.5 m length is 80^(@)C//m . It the temperature of hotter end of the rod is 30^(@)C , then the temperature of the cooler end is

Assume that the coefficient of linear expansion of the material of a rod remains constant, equal to alpha^(@)C^(-1) for a fairly large range of temperature. Length of the rod is L_0 at temperature theta_(0) . (a) Find the length of the rod at a high temperature theta . (b) Approximate the answer obtained in (a) to show that the length of the rod for small changes in temperature is given by L = L_0 [1 + alpha (delta- delta_(0))]

The coefficient of linear expansion of a rod of length 1 m, at 27^@C , is varying with temperature as alpha = 2/T unit (300 K le T le 600 K) , where T is the temperature of rod in Kelvin. The increment in the length of rod if its temperature increases from 27^@C to 327^@C is