Find the coordinates of the point on the curve `y=(x)/(1+x^(2))` where the tangent to the curve has the greatest slope.

Find the point on the curve y=(x)/(1+x^(2)) where the tangent to the curve has the greatest slope.

Find the coordinates of the point on the curve y=x/(1+x^2) where the tengent to the curve has the greatest slope .

The point on the curve y=x/(1+x^2) where the tangent to the curve has the greatest slope is

The coordinates of the point on the curve (x^(2)+ 1) (y-3)=x where a tangent to the curve has the greatest slope are given by

Find the coordinates of the point on the curve y=x-(4)/(x) , where the tangent is parallel to the line y=2x .

The coordinates of the point on the curve (x^(2)+1)(y-3)=x where a tangent to the greatest slope are given by

Find the coordinates of the point on the curve, y= (x^(2)-1)/(x^(2) + 1) (x gt 0) where the gradient of the tangent to the curve is maximum

Find the coordinates of the point on the curve x^2y - x + y = 0 where the slope of the tangent is maximum.