If `g` is the acceleration due to gravity and `R` is the radius of earth, then the dimensional formula for g `R` is

If g is the acceleration due to gravity at the earth’s surface and r is the radius of . the earth, the escape velocity for a body to escape out of earth’s gravitation field is :

If g is acceleration due to gravity on the surface of the Earth and R is radius of the Earth, then the gravitational potential on the surface of the Earth is

The escape velocity v of a body depends upon the acceleration due to gravity of the planet and the radius of the planet R. Establish dimensionally the relationship between v, g and R.

The satellite is moving round the earth (radius of earth = R) at a distance r from the centre of the earth. If g is the acceleration due to gravity on the surface of the earth. The acceleration of the satellite will be

IF g is the acceleration due to gravity on the earth's surface , then at a depth x acceleration due to gravity will be g (1- ( x) /( R )) - prove it . [ R is the radius of the earth ]

If R= radius of the earth and g= acceleration due to gravity on the surface of the earth, the acceleration due to gravity at a distance (r gt R) from the centre of the earth is proportional to

If R= radius of the earth and g= acceleration due to gravity on the surface of the earth, the acceleration due to gravity at a distance (r lt R) from the centre of the earth is proportional to

If R= radius of the earth and g= acceleration due to gravity on the surface of the earth, the acceleration due to gravity at a distance (r gt R) from the centre of the earth is proportional to

If R is the radius of the earth and g the acceleration due to gravity on the earth’s surface, the mean density of the earth is

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is