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Thecircle x^2+y^2-8x+4y+4=0 touches...

Thecircle `x^2+y^2-8x+4y+4=0` touches

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The circle x^2+y^2−8x+4y+4=0 touches: a) x axis b) y axis c) both the axis d) neither x axis nor y axis

The circle x^2 + y^2 - 8x + 4y +4 = 0 touches

If the circle x^2+y^2+8x-4y+c=0 touches the circle x^2+y^2+2x+4y-11=0 externally and cuts the circle x^2+y^2-6x+8y+k=0 orthogonally then k =

If the circle x^2+y^2+8x-4y+c=0 touches the circle x^2+y^2+2x+4y-11=0 externally and cuts the circle x^2+y^2-6x+8y+k=0 orthogonally then k =

If the circle x^(2)+y^(2)+8x-4y+c=0 touches the circle x^(2)+y^(2)+2x+4y-11=0 externally and cuts the circle x^(2)+y^(2)-6x+8y+k=0 orthogonally then k

The circle x ^(2) +y^(2) -8 x+4=0 touches -

The circle x^(2)+y^(2)+4x-4y-4=0 touches

The circle x^(2) + y^(2)- 8x + 4y + 4=0 touches