Graph between log x/m and log P is a straight line at angle of `45^(@)` with intercept 0.4771 on y-axis. Calculate the amount of gas adsorbed in gram per gram of adsorbent when pressure is 3 atm.

A graph between log (x/m) and log p is straight line at an angle of 45^(@) with intercept on y-axis equal to 0.3010. Calculate the amount of the gas adsorbed per gram of the adsobent when the pressure is 0.2 atm.

When a graph is plotted between log x/m and log p, it is straight line with an angle 45^(@) and intercept 0.3010 on y - axis. If initial pressure is 0.3 atm, what will be the amount of gas adsorbed per gram of adsorbent : (Report your answer after multiplying by 10)

When a graph is plotted between log x/m and log p, it is straight line with an angle 45^@ and intercept 0.6020 on y-axis.if initial pressure is 0.3 atm, what will be the amount of gas adsorbed per gram of adsorbent :

A graph between (x/m) vs log p gives a striaght line with slope equal to 45^(@) and intercept on the log (x/m) axis as 0.3 calculate the amount of gas adsorbed per gram of charcoal at a pressure of 0.95 atm

Graph between log x//m and log p is a straight line inclined at an angle of 45^@ . When pressure is 0.5 atm and 1n k = 0.693 , the amount of solute adsorbed per gram of adsorbent will be:

Graph between log x//m and log p is a straight line inclined at an angle of 45^@ . When pressure is 0.5 atm and 1n k = 0.693 , the amount of solute adsorbed per gram of adsorbent will be:

When a graph is plotted between log x//m and log p, it is straight line with an angle 45^(@) and intercept 0.3010 on y- axis . If initial pressure is 0.3 atm, what wil be the amount of gas adsorbed per gm of adsorbent :

When a graph is pplotted between log x//m and log p, it is straight line with an angle 45^(@) and intercept 0.3010 on y-axis. If initial pressure is 0.3 atm, what will be the amount of gas adsorbed per gm of adsorbent: