The enthalpy change `(Delta H)` for the reaction
`N_(2) (g)+3H_(2)(g) rarr 2NH_(3)(g)`
is `-92.38 kJ` at `298 K`. What is `Delta U` at `298 K`?

The enthalpy change (DeltaH) for the reaction, N_(2(g))+3H_(2(g)) rarr 2NH_(3g) is -92.38kJ at 298K What is DeltaU at 298K ?

The enthaply change (Delta H) for reaction, N_(2) (g) + 3H_(2)(g) to 2NH_(3) (g) is 92.38 kj at 298 K. What is Delta U at 298 K ?

The enthalpy change (DeltaH) for the reaction, NH_(2(g))+3H_(2(g)) rarr 2NH_(3g) is -92.38kJ at 298K What is DeltaU at 298K ?

The enthalpy change (DeltaH) for the reaction N_2(g) + 3H_2 (g) to 2NH_3(g) is -92.38 kJ at 298 K. What is DeltaU at 298 K ? (R = 8.314 j K^(-1) mol^(-1))

The enthalpy change (Delta H) for the reaction N_(2) (g) + 3 H_(2) (g) rarr 2 NH_(3) (g) is - 92.38 kJ at 298 K . The internal energy change Delta U at 298 K is

The enthalpy change for the reaction, N_2(g)+3H_2(g)rightarrow2NH_3(g) Is -92.38 kJ at 298 K. What is DeltaU at 298 K?

The enthalpy change for the reaction. N_(2(g))+3H_(2(g))rightarrow2NH_(3(g)) is - 91.8 kJ at 298 K.what is Delta U at 298K? ( R=8.314 JK^-1mol^-1 )