`(x^2-3. 5 x+1. 5)/(x^2-x-6)=0`

Simplify (x-3)/(x^(2)-x-6) + (2x-1)/(2x^(2) + 5x-3) - (2x +5)/(x^(2) + 5x +6)

lim_(x rarr0)(3x^(2)+5x-1)/(x^(2)+2x+6)

(x-1)/(x-2)-(x-2)/(x-3)=(x-5)/(x-6)-(x-6)/(x-7)

(5x^(2)-3x+4)/((x+1)(x^(2)-5x+6))=

((x+3)(x^(2)-5x+6))/((x^(2)+x+1)(x-4))<=0

If d/(dx) {f(x)}=1/(1+x^2) then d/(dx){f(x^3)} is a) (3x)/(1+x^3) b) (3x^2)/(1+x^6) c) (-6x^5)/(1+x^6)^2 d) (-6x^5)/(1+x^6)

Solve (x^(2)+(1)/(x^(2)))-5(x+(1)/(x))+6=0," when "x ne0