The equation of a diameter of circle x ^(2) + y^(2)-6x + 2y =0,` passing through origin is

The equation of the diameter of the circle x^(2) + y^(2) - 6x + 2y = 0 which passes through origin is

The equation of the diameter of the circle x^(2)+y^(2)+6 x-4 y-2=0 , passing through the point (2,-3) is

Equation of that diameter of circle x^(2) + y^(2) - 6x + 2y - 8 = 0 , which passes through origian , is

Equation of the diameter of the circle x^(2)+y^(2)-2x+4y=0 which passes through the origin is x+2y=0 b.x-2y=0 c.2x+y=0 d.2x-y=0

Equation of the diameter of the circle x^2+y^2-2x+4y=0 which passes through the origin is a.x+2y=0 b.x-2y=0 c. 2x+y=0 d. 2x-y=0.

The line x+3y=0 is a diameter of the circle x^(2)+y^(2)-6x+2y=0

The equation of one of the diameters of the circle x^2+y^2 - 6x + 2y =0 is:

Equation of the diameter of the circle x^(2) +y^(2) - 2x + 4y = 0 which passes through the origin is