A surface irradiated with lihgt `lamda=480 nm` gives out electrons with maximum velocity v `ms^(-1)`, the cut off wavelength being 600 nm. The same surface would release electrons with maximum velocity `2vms^(-1)` if it is irradiated by light of wavelength.

A surface irradiated with light of wave length 480 nm gives out electron with maximum velocity v m/s, the cut off wave length being 600nm. The same surface would release electron with maximum velocity 2V, if it is irradiated by light of wave length

A metallic surface is irradiated with light energy E , of wave length lamda giving out electrons with maximum velocity 2m/s . The threshold wavelength of the metal surface is 3lamda The same surface would release electrons with maximum velocity of 4m/s if irradiated by light of wavelength (nm) (m is mass of electrons)

What is the effect on the maximum velocity of the emitted electron if the wavelength of the incident light is decreased?

The maximum velocity of electrons emitted from a metal surface is v. What would be the maximum velocity if the frequency of incident lightis increased by a factor of 4?

The maximum velocity of electrons emitted from a metal surface is v. What would be the maximum velocity if the frequency of incident lightis increased by a factor of 4?

The work function of cesium is 2.27 eV. The cut-off voltage wich stops the emission of electrons from a cesium cathode irradiated with light of 600 nm wavelength is

The velocity of electron is 1% of velocity of light . Calculate debrobile wavelength of electron.

A metal is irradiated with light of wavelength 600 nm. Given that the work function of the metal is 1.0 eV, the de Broglie wavelength of the ejected electron is close to: