A `CE` amplifier is designed with a transistor having `alpha =0.99`. Input impedance is `1 k Omega` and load is `10 k Omega`. Voltage gain will be :

A common emitter amplifier is designed with NPN transistor (alpha = 0.99) . The input impedance is 1 K Omega and load is 10 K Omega . The voltage gain will be

A common-emitter amplifier is designed with an n-p-n transistor (alpha=0.99) .The input impedance is 1kOmega and the load is 10kOmega .The voltage gain will be

A common-emitter amplifier is designed with an n-p-n transistor (alpha=0.99) .The input impedance is 1kOmega and the load is 10kOmega .The voltage gain will be

A common emitter amplifier is designed with NPN transistor (alpha=0.99) . The input impedence is 1k Komega and load is 10 Komega . The voltage gain will be

A common emitter amplifier is designed with n-p-n transistor (alpha=0.99) . The input resistance is 1K ohm and load is 10 k ohm . The voltage gain will be

The current gain in the CE mode of a transistor is 10. If the input impedance is 10 K Omega and load resistance = 60 K Omega , then the power gain will be

The current gain in the common emitter mode of a transistor is 10. The input impedance is 20kOmega and load of resistance is 100k Omega . The power gain is

The current gain in the common emitter mode of a transistor is 10. The input impedance is 20kOmega and load of resistance is 100k Omega . The power gain is

A common emitter amplifier has current gain 70. Its load resistance is 5 k Omega and input resistance is 500 Omega . The voltage gain is