`CdO` has `NaCl` like structure with density `8.27g//c c`. If the ionic radius of `O^(2-)` is `1.24A^(@)` determine the ionic radius of `Cd^(2+)`:

Cdo has NaCl structure with density 8.27 g/cc. If the ionic radius of O^(2-) is 1.24 Å , determine ionic radius of Cd^(2+)

O^(2-) and Si^(4+) are isoelectronic ions. If the ionicradius of O^(2-) is 1.4 A^(@) , the ionic radius of Si^(4+) will be

If the nuclear of radius of O^8 is 2.4 fermi, then radius of Al^27 would be

If the nuclear of radius of O^8 is 2.4 fermi, then radius of Al^27 would be

O^(2-) and Si^(4+) are isoelectronic ions. If the ionic radius of O^(2-) is 1A^(0) , the ionic radius of Si^(4+) will be

O^(2-) " and " Si^(4+) are isoelectronic ions. If the ionic radius of O^(2-) " is " 1A^(@) , the ionic radius of Si^(4+) will be

O^(2-) and Si^(4+) are isoelectronic ions. If the ionic radius of O^(2-) is 1.4 oversetoA , the ionic radius of Si^(4+) will be

What is point defect? A metal has cubic close packed crystal structure. Its density is 2.7 gcm^-3 . The radius of the metal atom is 1.43 A. Determine the atomic weight of the metal.

The ionic radius Na^+ ion 1.02 A^@ then ionic radius in A^@ of Mg^(2+) & Al^(3+) respectively.