From the point `P(16,7)`, tangents PQ and PR are drawn to the circle `x^2 +y^2 -2x-4y- 20=0` If C is the centre of the circle, then area of quadrilateral PQCR is

Two tangents PQ and PR drawn to the circle x^2 +y^2-2x-4y-20=0 from point P(16,7). If the centre of the circle is C, then the area of quadrilateral PQCR will be

If the tangents AB and AQ are drawn from the point A(3, -1) to the circle x^(2)+y^(2)-3x+2y-7=0 and C is the centre of circle, then the area of quadrilateral APCQ is :

If the tangents AB and AQ are drawn from the point A(3, -1) to the circle x^(2)+y^(2)-3x+2y-7=0 and C is the centre of circle, then the area of quadrilateral APCQ is :

From the point P(4,-4) tangents PA and PB are drawn to the circle x^(2)+y^(2)-6x+2y+5=0 whose centre is C then Length of AB

From the point P(-1,-2) ,PQ and PR are the tangents drawn to the circle x^(2)+y^(2)-6x-8y=0 .Then angle subtended by QR at the centre of the circle is

If tangents are drawn from origin to the circle x^(2)+y^(2)-2x-4y+4=0, then

Find the length of the tangent, drawn to the circles x^2+y^2+10x-6y+8=0 from the centre of the circle x^2+y^2-4x=0

From a point "P" on the line 2x+ y +4 = 0 which is nearest to the circle x^2 +y^2-12y+35=0 tangents are drawn to give circle. The area of quadrilateral PACB (where 'C' is the center of circle and PA & PB re the tangents.) is