For a transistor connected in common emitter mode, the voltage drop across the collector is 2V and beta is 50. If `R_(c)` is `2 kOmega`, the base current is `axx10^(-5) A`. What is the value of a ?

A transistor connected in common emitter mode, the voltage drop across the collector is 2 V and beta is 50, the base current if R_C is 2 kOmega is

A transistor connected in common emitter mode, the voltage drop across the collector is 2 V and beta is 50, the base current if R_C is 2 kOmega is

For a transistor connected in common emitter mode, the voltage drop across the collector is 2V and beta is 50. Find the base current is R_(C) is 2K

For a transistor connected in common emitter mode , the voltage drop across the collector is 2 V and beta is 50 . Find base current if R_(C) is 2K .

A transistor is connected in common emitter mode. The collector supply is 10 volt and the voltage drop across resistor of 1 kOmega in the collector circuit is 0.5 volt. If the current gain beta is 49, then

For a Common emitter emplifer the voltage across collector resistance 2kOmega is 2V. If the current amplification factor is 200 and base resistance is 1.5Omega , what is the inpur voltage?

The potential difference across the collector of a transistor, used in common emitter mode is 1.5V , with the collector resistance of 3 kOmega . Find (i) the emitter current and (ii) the base current, if d.c. gain of the transistor is 50.

A transistor is connected in common-emitter (CE) configuration.The collector-supply is 10 V and the voltage drop across 500 Omega in the collector circuit is 4 V. If the current-gain factor (alpha) is 0.96, the base-current is