Ammonium chloride crystallizes in a body-centred cubic lattice with a unit distance of 387 pm. If the size of `Cl^(-)` ion is 181pm, the size of `NH_(4)^(+)` ion would be

Ammonium chloride, crystallizes in a body centered cubic lattice with edge length of unit cell equal to 387pm. If the size of Cl^(-) ion is 181pm, the size of NH_(4)^(+) ion would be:

Ammonium chloride, crystallizes in a body centered cubic lattice with edge length of unit cell equal to 387pm. If the size of Cl^(-) ion is 181pm, the size of NH_(4)^(+) ion would be:

Ammonium chloride, crystalliazes in a body centered cubic latteice iwh edge length of unit cell equal to 387pm. If the size of Cl^(-) ion is 181pm, the size of NH_(4)^(+) ion would be:

Ammonium chloride, crystalliazes in a body centered cubic latteice iwh edge length of unit cell equal to 387pm. If the size of Cl^(-) ion is 181pm, the size of NH_(4)^(+) ion would be:

Ammonium chloride crystallizes in a body centred cubic lattice with edge length of unit cell of 390 pm. If the size of chloride ion is 180 pm, the size of ammonium ion would be

Ammonium chloride crystallises in a body-centred cubic lattice with a unit distance of 387 pm. Calculate (a) the distance between oppositely charged ions in the lattice and (b) and radius of the NH_(4)^(+) ion of the radius of Cl^(-) ion is 181 pm.

The edge length of sodium chloride unit cell is 564 pm. If the size of Cl^(-) ion is 181 pm. The size of Na^(+) ion will be

A metal crystallizes in a body-centred cubic lattice with the unit cell length 320 pm. The radius of the metal atom (in pm) will be

A metal crystallizes in a body-centred cubic lattice with the unit cell length 320 pm. The radius of the metal atom (in pm) will be