If the perpendicular distance of the line (x/a)+(y/b)=1 from the origin is `p//sqrt(2)` show that `a^(2),p^(2),b^(2)` are in Harmonic Progression.

If p is the length of the perpendicular drawnfrom the origin upon the line (x)/(a)+(y)/(b)=1 and a^(2),p^(2),b^(2) are in arithmetic progression,) then |ab| is equal to

Transform the equation x/a+y/b=1 into normal form where agt0, bgt0 . If the perpendicular distance of the straight line from the Origin is p then deduce that 1/(p^(2))=1/(a^(2))+1/(b^(2))

If p is the perpendicular distance from the origin to the straight line x/a+y/b=1 , then 1/(a^(2))+1/(b^(2))=

if P is the length of perpendicular from origin to the line x/a+y/b=1 then prove that 1/(a^2)+1/(b^2)=1/(p^2)

if P is the length of perpendicular from origin to the line x/a+y/b=1 then prove that 1/(a^2)+1/(b^2)=1/(p^2)

If 2p is the length of perpendicular from the origin to the lines (x)/(a)+(y)/(b)=1, then a^(2),8p^(2),b^(2) are in

If the length of perpendicular from origin to the line ax+by+a+b=0 is p , then show that : p^(2)-1=(2ab)/(a^(2)+b^(2))

If p be the length of the perpendicular from the origin on the line x/a+y/b=1 , then