A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to -`(K//r^(2))`. Where K is constant. What is the total energy of the particle?

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to (-K//r^(2)) , where k is a constant. The total energy of the particle is -

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to (-K//r^(2)) , where k is a constant. The total energy of the particle is -

A particle of mass .m. is moving in a horizontal circle of radius .r. under a centripetal force equal to -(k)/(r^(2)) , where k is a constant. The potential energy of the particle

A particle of mass m is revolving in a horizontal circle of radius r under a centripetal force k//r^(2) where k is a constant. What is the total energy of the particle ?

A particle of mass m is moving in a horizontal circle of radius r under centripetal force given by (- k//r^(2)) where k is a constant . Then the total energy of the particle is _________ .