If a block moving up an inclined plane at `30^(@)` with a velocity of 5 m/s, stops after 0.5 s, then coefficient of friction will be nearly

If a block moving up at theta = 30^(@) with a velocity 5m/s, stops after 0.5 sec, then what is mu

A block starts moving up a fixed inclined plane of inclination 60^(@)C with a velocityof 20 ms^(-1) and stops after 2s. The approximate value of the coefficient of friction is [g = 10 ms^(-2) ]

A block starts moving up a fixed inclined plane of inclination 60^(@)C with a velocityof 20 ms^(-1) and stops after 2s. The approximate value of the coefficient of friction is [g = 10 ms^(-2) ]

A block is projected upwards with a velocity of 5 m/s from the bottom of a rough inclined plane of inclination 30° with the horizontal. It stops after 0.5 s. What is the coefficient of friction ? (g =10m//s^2 )

Block of mass 10 kg is moving on inclined plane with constant velocity 10 m/s. The coedfficient of kinetic friction between incline plane and block is :-

Block of mass 10 kg is moving on inclined plane with constant velocity 10 m/s. The coedfficient of kinetic friction between incline plane and block is :-

Block of mass 10 kg is moving on inclined plane with constant velocity 10 m/s. The coedfficient of kinetic friction between incline plane and block is :-

A block starts moving up an inclined plane of inclination 30^@ with an initial velocity of v_0 . It comes back to its initial position with velocity (v_0)/(2) . The value of the coefficient of kinetic friction between the block and the inclined plane is close to I/(1000) , The nearest integer to I is ____________ .