`x^4-2x^2-63)<=0`

Solve x^(4)-2x^(2)-63<=0

D={x:0<=4x^(2)<=1}

Solve: 3/2(2-4x)-4/5(3-2x)+(63)/5=0

Solve (x^2-4)sqrt(x^2 -1) lt 0.

Solve (x^2-4)sqrt(x^2 -1) lt 0.

Solve (x^2-4)sqrt(x^2 -1) lt 0.

Discuss the continuity of the function f at x = 0 and x = 2, where f is given as : f(x) ={((sin3x)/(sin4x),; -1lt= x lt=0), (3x+3/4,; 0lt x lt2), ((x^2+x-6)/(x-2),; 2lt= x lt=4):}

((x ^ (2) + 4x + 6) (x ^ (2) + x + 1)) / (x ^ (2) -x + 1) <= 0