Prove that,`64cos^(3) theta sin^(4) theta = cos 7 theta - cos 5 theta - 3 cos 3theta+3 cos theta`

64cos^(3)theta sin^(4)theta=cos7 theta-cos5 theta-3cos3 theta+3cos theta

64cos^(3)theta sin^(4)theta=cos7 theta-cos5 theta-3cos3 theta+3cos theta

2 cos theta - cos 3 theta - cos 5 theta - 16 cos^(3) theta sin^(2) theta =

( cos 3 theta - sin 3 theta )/( cos theta+ sin theta ) =

Prove that: (sin theta - 2 sin^(3) theta) = (2cos^(3) theta - cos theta) tan theta .

(sin ^ (3) theta + sin3 theta) / (sin theta) + (cos ^ (3) theta-cos3 theta) / (cos theta) =

Prove that, cos^(3) theta cos 3 theta + sin^(3) theta sin 3 theta = cos^(3) 2 theta

Prove the following : cos 3 theta+ cos 5 theta+ cos 7 theta+ cos 9 theta= 4 cos theta cos 2 theta cos 6 theta .

( sin 3 theta )/( sin theta ) -(cos 3 theta )/( cos theta )=

Prove that (cos^3 theta-sin^3 theta)/(cos theta-sin theta) = 1+cos theta sin theta