Home
Class 12
PHYSICS
A stone of mass 1 kg is tied to a string...

A stone of mass 1 kg is tied to a string 2m long and it's rotated at constant speed of 40 `ms^(-1)` in a vertical circle. The ratio of the tension at the top and the bottom is
[Take g=10m`s^(2)`]

Promotional Banner

Similar Questions

Explore conceptually related problems

A stone of mass 1 kg tied to a string 4 m long and is rotated at constant speed of 40 m/s a vertical circle. The ratio of the tension at the top and the bottom, is (g=10" m"//"s"^(2))

A stone of mass 1 kg tied to a string 4 m long and is rotated at constant speed of 40 m/s a vertical circle. The ratio of the tension at the top and the bottom, is (g=10" m"//"s"^(2))

A stone of mass m is tied to a string of length l and rotated in a circle with a constant speed v . If the string is released, the stone flies

A particle of mass m is rotating by means of a string in a vertical circle . The difference in tension at the top and the bottom revolution is

A particle of mass m is rotating by means of a string in a vertical circle . The difference in tension at the top and the bottom revolution is

A stone of mass 50 g is tied to the end of a string 2 m long and is set into rotation in a horizontal circle with a uniformspeed of 2 m//s . Then tension in the string is

A stone of mass 50 g is tied to the end of a string 2 m long and is set into rotation in a horizontal circle with a uniforn speed of 2m//s .Then tension in the string is