f(x)=x(x-4)^(2)," अन्तराल "[0,4]" में "

f(x)=x(x-4)^(2), interval [0,4]

If LMVT is applicable for f(x)=x(x+4)^(2), x in [0,4], then c=

The function f(x)= x^(2)-4x, x in [0,4] attains minimum value at

If f(x) = (|x-4|)/(4-x), x ne 4, f(4) = 0 , show that f is continuous every where except at x = 4.

Examine the continuity of the function f(x) = {((|x-4|)/(2(x-4))",","if" x ne 4),(0",","if" x = 4):} at x=4

f(x)= {{:((|x-4|)/(2(x-4)), if x ne 4),(0,if x = 4):} at x = 4 .

f(x)= {{:((|x-4|)/(2(x-4)), if x ne 4),(0,if x = 4):} at x = 4 .

f(x) = (1 - cos (4x))/(x^(2)) , x in 0, f (0) = 8 , at x =0 f is