[" Q.18A force "vec F=6hat i-8hat j+10hat k" Newton produces an acceleration of "1m/s^(2)" in a body.The "],[" body would be "]

A body, under the action of a force F=6hat(i)-8hat(j)+10hat(k) acceleration of 1ms^(-2) . The mass of this body must be

A body, under the action of a force F=6hat(i)-8hat(j)+10hat(k) acceleration of 1ms^(-2) . The mass of this body must be

A body under the action of a force vec(F)=6hat(i)-8hat(j)N acquires an acceleration of 5ms^(-2) . The mass of the body is

A body under the action of a force vec(F)=6hat(i)-8hat(j)N acquires an acceleration of 5ms^(-2) . The 10s mass of the body is

A force vector applied on a mass is represented as vec(F)=6hat(i)-8hat(j)+10hat(k) and acceleration with m//s^(2) . What will be the mass of the body in kg.

Vectors vec A=hat i+hat j-2hat k and vec B=3hat i+3hat j-6hat k are

If vec a = 6hat i - hat j+ 2hat k and vec b =hat i- 3hat j - 2 hat k , find vec a - vec b .

A 10 kg object is subjected to two forces ( in newton ) vec(F)_(1) = 16 hat (i) - 11 hat (j) and vec(F) _(2) = 8 hat (i) + 18 hat (j), , the magnitude of resulting acceleration in ms^(-2) will be

A 10 kg object is subjected to two forces ( in newton ) vec(F)_(1) = 16 hat (i) - 11 hat (j) and vec(F) _(2) = 8 hat (i) + 18 hat (j), , the magnitude of resulting acceleration in ms^(-2) will be