y=Ax+(B)/(x)

If y= f(x) =(ax-b)/(bx-a) , prove that f(y) =x.

If y=ax^(5)+(b)/(x^(4))," then "(d^(2)y)/(dx^(2))=

If y=ax^(5)+(b)/(x^(4))," then "(d^(2)y)/(dx^(2))=

If y = ax ^(4) + (b)/(x ^(3)), then (d ^(2) y)/( dx ^(2)) =

y = f(x) = (ax-b)/(cx-a) then f(y) = ?

One of the diameters of the circle circumscribing the rectangle ABCD is 4y=x+7 . If A and B are the points (-3, 4) and (5, 4) and slope of the curve y = (ax)/(b-x) at point (1, 1) be 2 , then centre of circle is : (A) (a, b) (B) (b, a) (C) (-a, -b ) (D) (a, -b)

(i) If y = f(x) = (3x-1)/(5x-3) , prove that f(y) = x (ii) If y = f(x) = (ax -b)/(bx-a) , prove that f(y) = x

If f(x)= y = (ax-b)/(cx-a) , then prove that f(y) = x

If y = ax ^(2) + b// x then x ^(2) y _(2) =

y = (ax + b) e^(-2x)