" If "A+B+C=180^(@)" then "(sin2A+sin2B+sin2C)/(cos A+cos B+cos C-1)=

If A+B+C=180^(@)C then (sin 2A+sin 2B+sin 2C)/(cos A +cos B +cos C-1)=

If A+B+C=180^(@), show that sin2A-sin2B-sin2C=-4sin A cos B cos C

If A+B+C=180^(@), prove that sin2A+sin2B-sin2C=4cos A cos B sin C

If A+B+C=pi then prove that sin2A-sin2B+sin2C=4cos A sin B cos C

If A+B+C=90^(@) then (cos2A+cos2B+cos2C-1)/(sin A sin B sin C)=

In a triangle ABC if (sin2A+sin2B+sin2C)/(cos A+cos B+cos C-1)=((lambda)/(2))cos((A)/(2))cos((B)/(2))cos((C)/(2)) then lambda equals

If A+B+C=90^(@) then (cos 2A+cos 2B+cos 2C-1)/(sin A sin B sin C)=

Prove that : (sin 2A+sin 2B + sin 2C)/(cos A + cos B + cos C-1) = 8 cos(A/2) cos( B/2) cos( C/2)