`(x^2+7x+10)/(x+2/3)>0`

The number real of roots of sqrt(x - 3) (x^(2) + 7x + 10)= 0 , where x in R is

lim_(xrarr0) ((3x^2 + 2)/ (7x^2 +2))^(1/x^2) is equal to

lim_(xrarr0) ((3x^2 + 2)/ (7x^2 +2))^(1/x^2) is equal to

Solve each of the following equations and also check your result in each case: ((45-2x))/(15)-((4x+10))/5=((15-14 x))/9 5((7x+5)/3)-(23)/3=13-(4x-2)/3 (7x-1)/4-1/3\ (2x-(1-x)/2)=(10)/3 (0. 5(x-0. 4))/(0. 42\ )-(0. 6(x-2. 71))/(0. 42)=x+6. 1

f(x)=(2^x+2^(-x)(tanx)sqrt(tan^-1(2x^2-3x+1)))/(7x^2-3x-1)^3 , then find f'(0)

6x^(2)+7x-10=0

Evaluate : int_(-sqrt(2))^(sqrt(2))(2x^7+3x^6-10 x^5-7x^3-12 x^2+x+1)/(x^2+2)dx