Show that the angle between the circles
`x^2 + y^2 = a^2,x^2 + y^2 = ax + ay ` is `(3pi)/(4)`.

The angle between the curves : y^(2)=4ax and ay=2x^(2) is :

The angle between the curves y^(2)=4ax and ay=2x^(2) is

The angle between the two circles x^(2)+y^(2)=4 and x^(2)+(y-1)^(2)=4 is

The angle between the circles x^2+y^2-2x-4y+3=0 and x^2+y^2-4x-6y+11=0 is

The angle between the circles x^2+y^2-2x-4y+3=0 and x^2+y^2-4x-6y+11=0 is

The angle between curves y^2=4ax,ay=2x^2 is

Find the area included between the curves y^2 = 4ax and x^2 = 4ay, a>0 .

Find the area between the curves y^(2) = 4ax and x^(2)=4ay .

The area between the parabolas y^2 = 4ax and x^2 = 8ay is …… Sq. units .

If the angle between the circles x^(2) +y^(2) +4x - 5 = 0 and x^(2) +y^(2) +2lambda y- 4 = 0 "is" (pi)/(3), " then " lambda =