If `theta` is the acute angle between the pair of the lines `x^2 + 3xy – 4y^2 = 0` then `sin theta =`

If theta is the acute angle between the pair of the lines x^(2)+3xy4y^(2)=0 then sin theta=

If theta is the acute angle between the pair of lines 5x^2-8xy-y^2=0 then find cos theta

Find the acute angle between the pair of lines given by : x^2 + 2xy - 4y^2 = 0

If theta is acute angle between the pair of lines x^(2)-3xy+2y^(2)+3x-5y+2=0 then sintheta=

Findthe angle between the pair of straight lines x^2 -4y^2+3xy = 0

If theta is the acute between the pair of lines x^(2)+3xy-4y^(2)=0 then sin theta=

11.The acute angle between the pair of lines x^(2)+2xy cot theta+y^(2)=0 is

If theta is the angle between the pair of straight lines x^(2)-5xy+4y^(2) + 3x-4=0 , then tan^(2) theta is equal to

If theta is the acute angle butween the pair of lines represented by 3x^(2)-8xy+4y^(2)=0 then (2cos theta+3sin theta)/(4sin theta+5cos theta) is

If theta is the acute angle between the lines given by ax^(2) + 2hxy + by^(2) = 0 then prove that tan theta = |(2 sqrt (h^(2) - ab))/(a + b)| . Hence find acute angle between the lines 2x^(2) + 7xy + 3y^(2) = 0