Prove that,`"cos" pi/11 "cos" (2pi)/11 "cos" (3pi)/11 "cos" (4pi)/11 "cos" (5pi)/11 = 1/32`

"Show that : " "cos" pi/11 +"cos"(3pi)/11+ "cos" (5pi)/11+ "cos" (7pi)/11+"cos" (9pi)/11 =1/2 .

Show that cos(pi/11)cos((2pi)/11)cos((3pi)/11)cos((4pi)/11)cos((5pi)/11)=1/32

cos(pi/11) cos((2pi)/11) cos((3pi)/11)....cos((11pi)/11)=

Prove that cos. (pi)/(11). cos . (2 pi)/(11). cos . (3 pi)/(11) cos. (4 pi)/(11). cos . (5 pi)/(11)=(1)/(32)

Prove that "cos"(pi)/9."cos"(2pi)/9."cos"(3pi)/9."cos"(4pi)/9=1/(2^(4))

Find the value "cos"(pi)/(11)+"cos"(3pi)/(11)+"cos"(5pi)/(11)+"cos"(7pi)/(11)+"cos"(9pi)/(11)

Given, cos 2^(m) theta cos 2^(m + 1) theta….cos 2^(n)theta = (sin 2^(n+1)theta)/(2^(n-m+1)sin 2^(m)theta)"where"2^(m) theta ne kpi, n, m, k in I solve the following "cos" (pi)/(11) "cos" (2pi)/(11) "cos" (3pi)/(11)..."cos" (10pi)/(11) is equal to

cos (pi)/(11)+cos (3 pi)/(11)+cos (5 pi)/(11)+cos (7 pi)/(11)+cos (9 pi)/(11)=