" Hiv) "(sin A)/(3)=(sin B)/(3)=(sin C)/(4)" इढ़ "6" माड "6,cos C=(1)/(9)" । "

If (sin A)/3 = (sin B)/3 = (sin C)/4 , then prove that, cos C=1/9 .

In Delta ABC , if ( sin A)/(4) = (sin B)/(5) = (sin C)/( 6) then the value of cos A +cos B +cos C =

If in a triangle ABC,(sin A)/(4)=(sin B)/(5)=(sin C)/(6), the value of cos A+cos B+cos C is equal to

Theorem 3:cos A+cos B+cos C=1+4(sin A)/(2)(sin B)/(2)(sin C)/(2)

(cos A)/(sin B sin C)+(cos B)/(sin C sin A)+(cos C)/(sin A sin B)=2

In a /_ABC,sin^(4)A+sin^(4)B+sin^(4)C=(3)/(2)+2cos A cos B cos C+(1)/(2)cos2A cos2B cos2C

If in a triangle ABC, 4 sin A= 4 sin B=3 sin C , the cos C=

lim_(xrarr0)((10"sin"9x)/(9"sin"10x))((8"sin"7x)/(7"sin"8x))((6"sin"5x)/(5"sin"6x))((4"sin"3x)/(3"sin"4x))(("sin"x)/("sin"2x)) is equal to a) 63/(256) b) 1/(6) c) 6/(5) d) 1/(2)

If (b+c)/(5)=(c+a)/(6)=(a+b)/(7) then sin A:sin B:sin C=4:3:2