`(dy)/(dx)tany=sin(x+y)+sin(x-y)`

(dy)/(dx)+y=sin x

(dy)/(dx)=sin (x+y)

(dy)/(dx)=sin(x+y)

(dy)/(dx)=sin(x-y)

Statement-1: Solution of the differential equation dy/dx tany=sin(x+y)+sin(x-y) is secy+2cosx=c .Statement-2: The differential equation dy/dx tany=sin(x+y)+sin(x-y) is (A) Both 1 and 2 are true and 2 is the correct explanation of 1 (B) Both 1 and 2 are true and 2 is not correct explanation of 1 (C) 1 is true but 2 is false (D) 1 is false but 2 is true

Solution of the differential equation tany (dy)/(dx)=sin(x+y)+sin(x-y) is -

(tany)(dy)/(dx)=sin(x+y)-sin(x-y) A) secy tany = 2 sin x+c B) log(cosy-coty)=2sin x+c C) log(secy+tany)=2sin x+c D) secy+tany=c.e^(sinx)

Solution of, (dy)/(dx)+sin[(x+y)/2]=sin[(x-y)/2] is: (A) ln|tany/2|+2sin(x/2)=c (B) ln|tan(y/4)|+2sin(x/2)=c (C) ln|tany/2|-2sin(x/2)=c (D) none of these

(dy) / (dx) = sin (x + y)