The equation to the perpendicular from the point `(alpha, beta gamma)` to the plane `ax+by+cz+d=0` is

The foot of the perpendicular from the point (alpha,beta,gamma) on Y-axis is

Find the equation of the plane through the point (alpha,beta,gamma) and parallel to the plane ax+by+cz=0

reflection of the point (alpha, beta, gamma) in the XY-plane is :

Reflexion of the point (alpha, beta, gamma) in XY plane is

Reflection of the point (alpha, beta, gamma) in XY plane is

The reflection of the point (alpha,beta,gamma) in the xy plane is

The reflection of the point (alpha,beta,gamma) in the xy-plane is:

The equations of the line through the point (alpha, beta, gamma) and equally inclined to the axes are (A) x-alpha=y-beta=z-gamma (B) (x-1)/alpha=(y-1)/beta=(z-1)/gamma (C) x/alpha=y/beta=z/gamma (D) none of these

The equation of the plane passing through (alpha,beta, gamma) and parallel to ax+by+cz=0 is