Home
Class 12
MATHS
The equation of the plane passing throug...

The equation of the plane passing through the point (1, -3, -2) and perpendicular to the planes `x+2y+2z=5` and `3x+3y+2z=8` is -

Promotional Banner

Similar Questions

Explore conceptually related problems

Obtain the equation of the plane passing through the point (1,-3,-2) and perpendicular to the plane x+2y+2z=5 and 3x+3y+2z=8 .

Find the equation of the plane passing through the point (-1,3,2) and perpendicular to the planes x+2y+2z=5 and 3x+3y+2z=8 .

Obtain the equation of the plane passing through the point (1, -3, -2) and perpendicular to the planes x+2y+2z=5\ a n d\ 3x+3y+2z=8.

Obtain the equation of the plane passing through the point (1, -3, -2) and perpendicular to the planes x+2y+2z=5\ a n d\ 3x+3y+2z=8.

The equation of the plane passing through the point (1,1,1) and perpendicular to the planes 2x+y-2z=5 and 3x-6y-2z=7

The equation of the plane passing through the point (1,1,1) and perpendicular to the planes 2x+y-2z=5 and 3x-6y-2z=7

The equation of the plane passing through the point (1,2,-3) and perpendicular to the planes 3x+y-2z=5 and 2x-5y-z=7 ,is

Find the equation of the plane passing through the point(-1, 3, 2) and perpendicular to the planes x + 2y + 3z = 5 and 3x + 3y + z = 0.

The equation of the plane passing through the point (1,2,-3) and perpendicular to the planes 3x+y-2z=5 and 2x-5y-z=7 is

The equation of the plane passing through the point (1,1,1) and perpendicular to the planes 2x+y-2z=5 and 3x-6y-2z=7 is