The amount of `._(6)C^(14)` isotope in a piece of wood is found to be one-fifth of that present in a fresh piece of wood. Calculate the age of wood (Half life of `C^(14) = 5577` years)

The amount of ._(6)^(14)C isotope in a piece of wood is found to one fourth (1/4) of that present in a fresh piece of wood. Calculate the age of the piece of wood (t_(12) "of "_(6)^(14)C=5770 "years") a) 7999 year b) 11543 year c) 16320 year d) 23080 year

The amount of C-14 in a piece of wood is found to be 1/6 of the amount present in a fresh piece of wood. What is the age of the wood ? (t_(1//2) for C-14 =5770 years)

A piece of wood was found to have C^(14)/C^(12) ratio 0.7 times that in a living plant.Calculate the period when the plant died. Half-life of C^(14)= 5760 years

The C-14 content of an ancient piece of wood was found to have three tenths of that in living trees. How old is that piece of wood? (log 3= 0.4771, log 7 = 0.8540 , Half-life of C-14 = 5730 years )

The ._(6)C^(14) and ._(6)C^(12) ratio in a piece of woods is 1//16 part of atmosphere. Calculate the age of wood. t_(1//2) "of" C^(14) is 5577 years?