`(x^2-1)/(2x+5)<3`

Integrate the following w.r.t.x. (2x^(2)-1)/((x^(2)+5)(x^(2)+4))

Solve the inequality: (x^(2)-1)/(x^(2)+1)+x^(2)-5x+6<0

Add: (3x^(2) - (1)/(5)x + (7)/(3)) + ((-1)/(4)x^(2) + (1)/(3)x - (1)/(6)) + (-2x^(2) - (1)/(2)x + 5)

(2x^(2)-1)/((x-1)(2x^(2)+5x+2))=

If (x+4)^3+(2x+1)^3+(2x+5)^3= (3x +12) (2x +1)(2x +5) , then what is the value of x ? यदि (x+4)^3+(2x+1)^3+(2x+5)^3= (3x +12) (2x +1)(2x +5) है, तो x का मान ज्ञात करें |

integrate this int ( x^2+1)/(x^2-5x+6)dx

integrate this int ( x^2+1)/(x^2-5x+6)dx

Evaluate: int(x^2+1)/(x^2-5x+6)dx

Find: int (x^2+1)/(x^2-5x+6)dx

(2x^(2)-1)/((x^(2)+4)(x^(2)-5))