`20/((x-3)(x-4))+10/(x-4)+1>0`

(20)/((z-3)(z-4))+(10)/(x-4)+1>0

Solve for x:(x-1)/(x+2)+(x-3)/(x-4)=(10)/(3),x!=-2,4

Solve for x : (x-1)/(x+2)+(x-3)/(x-4)=(10)/3,\ \ x!=-2,\ 4

Solve : ((x-1)^2(x-2)^3(x-4))/((x+1)(x+3)^4) ge0

((4x-3) / (2x + 1))-10 ((2x + 1) / (4x-3)) = 3, x! =-1/2, 3/4

Solve for x in (4x-1)/(4x+1)+(4x+1)/(4x-1)=(10)/(3)

x^2-2x+2=0"( 2)"x^2-3x+3=0x^2-3x+4=0"( 4)"x^2-5x+5=0 A quadratic equation whose roots are cosec20 andsec 0 can be(1) x2-2x+ 2 =0(2) x2-3x + 3 = 0(3) x2-3x+ 4= 0(4) x-5x+5= 0

Solve the following Q.E.: (i) 3x^(2)-4x+(20)/(3)=0 (ii) 27x^(2)-10x+1=0

If |(1,x,x^(2)),(x,x^(2),1),(x^(2),1,x)|=3 then find the value of |(x^(3)-1,0,x-x^(4)),(0,x-x^(4),x^(3)-1),(x-x^(4),x^(3)-1,0)|