The graph of `t_(1//2)` versus initial concentration 'a' is for

Draw the graph of half-life period (t_(1/2) versus initial concentration of reactant ([A[_0) for a zero order reaction. Give reasons in favour of your answer.

What will be the order of reaction for a chemical change having following graph of log t_1/2 versus log a? (a = initial concentration of reaction: t_1/2 = half-life)

Plot the graph of t t_(1//2) vs concentration for first order and zero order reaction.

Draw the graph of half-life period ( t_(1//2)) versus initial concentration of reactant (A)_(0) for a zero order reaction. Given reasons in favour of your answer.

For which order reaction a straight line is obtained along with x -axis by plotting a graph between half-life (t_(1//2)) and initial concentration 'a'

For the reaction AtoB , for which graph between half life (t_(1//2)) and initial concentration (a) of the rectant is given below Hence graph between -(d[A])/(dt) and time will be:

For the reaction AtoB , for which graph between half life (t_(1//2)) and initial concentration (a) of the rectant is given below Hence graph between -(d[A])/(dt) and time will be:

For the reaction AtoB , for which graph between half life (t_(1//2)) and initial concentration (a) of the rectant is given below Hence graph between -(d[A])/(dt) and time will be:

Following is the graph between log t_(1//2) and log a ( a initial concentration) for a given reaction at 300K Find the order of reaction.