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Calculate the enthalpy of combustion of ethylene .
Given : `C_(2) H_(6) (g) + (7)/(2) O_(2) (g) to 2 CO_(2) + 3 H_(2)O (l) , Delta H = = 1562 kJ* mol^(-1)`
`H_(2) (g) + (1)/(2) O_(2) (g) to H_(2) O (l) , Delta H = -286 kJ * mol^(-1)`
`C_(2) H_(4) (g) + H_(2) (g) to C_(2) H_(6) (g) , Delta H = -32 kJ * mol^(-1)`

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Calculate the enthalpy change for the reaction: C_(2)H_(4)(g)+3O_(2)(g) to 2CO_(2)(g)+2H_(2)O(l) Given: C_(2)H_(6)(g)+(7)/(2)O_(2)(g) to 2CO_(2)(g)+3H_(2)O(l),DeltaH^(0)=-1562.0kJ H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l),DeltaH^(0)=-286.0kJ C_(2)H_(4)(g)+H_(2)(g)toC_(2)H_(6)(g),DeltaH^(0)=-32.0kJ

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