" The area bounded by the curve "|(z)/(9)|+|(y)/(9)|=log_(b)^(a)log_(b)^(b)," where "a,b>0" and "a!=b=1" is "

The area bounded by curve |(x)/(9)|+|(y)/(9)|=log_(b)a xx log_(a)b where a,b>0a!=b!=1 is

The area bounded by curve |x/9|+|y/9|=log_b axxlog_a b where a,b > 0, a !=b != 1 is

The area of figure bounded by the curves y=a^(x)(a>1) and y=b^(-x)(b>1) and the straight line x=1 is (1)(1)/(log a)(a-1)+(1)/(log b)((1)/(b)-1)(2)log a(a-1)+log b((1)/(b)-1)(3)(1)/(log a)(a-1)+log b(b-1)(4)log a(a-1)+log b(b-1)

Solve the system of equations (ax)^(log_(c)a)=(by)^(log_(e)y);b^(log_(e)x)=a^(log_(e)y) where a>0,b>0 and a!=b,ab!=1

If (log_(3)(a))^(3)+(log_(b)(3))^(3)+9log_(b)(a)=27 Then the value of a is

The area bounded by the curve y=2^(x), the x- axis and the left of y-axis is (A) log _(e)2(B)log_(e)4 (C) log_(4)e(D)log_(2)e

If x=log_(b)a,y=log_(c)b,z=log_(a)c then xyz=

Solve :2log_(x)a+log_(ax)a+3log_(b)a=0 where a>0,b=a^(2)x

prove that a^(x)-b^(y)=0 where x=sqrt(log_(a)b) and y=sqrt(log_(b)a),a>0,b>0 and a,b!=1

If m;a;b>0;a!=1;b!=1; then log_(a)(m)=(log_(b)(m))/(log_(b)(a))