Consider 3 non-collinear points A, B,C with coordinates (0, 6), (5, 5) and (-1,1) respectively Equation of a line tangent to the circle circumscribing the triangle ABC and passing through the origin is:

The cartesian equation of a line passing through the origin and point (5,-2,3) is

In a triangle,ABC,the equation of the perpendicular bisector of AC is 3x-2y+8=0. If the coordinates of the points A and B are (1,-1)&(3,1) respectively,then the equation of the line BC & the centre of the circum-circle of the triangle ABC will be

In a triangle, ABC, the equation of the perpendicular bisector of AC is 3x - 2y + 8 = 0 . If the coordinates of the points A and B are (1, -1) & (3, 1) respectively, then the equation of the line BC & the centre of the circum-circle of the triangle ABC will be

Let A (0,7,10), B (-1,6,6,) and C (-4,9,6) are the vertices of a triangle. Find the coordinate of the centre of the circle passing through the point A,B,C.

The equation of the circle circumscribing the triangle formed with coordinate axes and the line with slope -2 and passing through (2,2) is

Points A(3,5) , B (-1,4) and C( 7,-6) are the vertices of Delta ABC. Find the coordinates of the centroid of the triangle

Find the equation of the line passing through the points (1,3) and (5,6).

Let A(5,6), B(-2,3) and C(6,-1) be the vertices of Delta ABC . Find the coordinates of the centroid of the triangle.

A(5, 4), B(–3, –2) and C(1, –8) are the vertices of a triangle ABC. Find the equations of median AD and line parallel to AC passing through the point B.

Orthocentre of an acute triangle ABC is at the orogin and its circumcentre has the coordinates ((1)/(2),(1)/(2)). If the base BC has the equation 4x-2y=5, then the radius of the circle circumscribing the triangle ABC, is sqrt(5/2) b.sqrt(3) c.(3)/(sqrt(2)) d.sqrt(6)