Consider the system of equations
`2x+lambday+6z=8`
`x+2y+muz=5`
`x+y+3z=4`
The system of equations has :
Exactly one solution if :

Consider the system of equations {:(2x+lambday+6z=8),(x+2y+muz=5),(x+y+3z=4):} The system of equations has : Infinitely many solutions if :

Consider the system of equations {:(2x+lambday+6z=8),(x+2y+muz=5),(x+y+3z=4):} The system of equations has : Infinitely many solutions if :

Consider the system of equations {:(2x+lambday+6z=8),(x+2y+muz=5),(x+y+3z=4):} The system of equations has : No solution if :

Consider the system of equations {:(2x+lambday+6z=8),(x+2y+muz=5),(x+y+3z=4):} The system of equations has : No solution if :

consider the system of equations : ltbr. 3x-y +4z=3 x+2y-3z =-2 6x+5y+lambdaz =-3 Prove that system of equation has at least one solution for all real values of lambda .also prove that infinite solutions of the system of equations satisfy (7x-4)/(-5)=(7y+9)/(13)=z

consider the system of equations : ltbr. 3x-y +4z=3 x+2y-3z =-2 6x+5y+lambdaz =-3 Prove that system of equation has at least one solution for all real values of lambda .also prove that infinite solutions of the system of equations satisfy (7x-4)/(-5)=(7y+9)/(13)=z

Consider the system of equation x+2y-3z=a , 2x+6y-11z=b , x-2y+7c then

Consider the system of equations x+y+z=6 x+2y+3z=10 x+2y+lambdaz =mu the system has infinite solutions if

Consider the system of equations x+y+z=6 x+2y+3z=10 x+2y+lambdaz =mu the system has unique solution if