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As shown in the figure, PA is a tangent ...

As shown in the figure, PA is a tangent to a circle and PBC is a secant, so that PB = AB. Prove that `PB.PC = AC^2`

Text Solution

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As PA is tangent to circle and PBC is a secant. So, from secant rule:
`PA^2 = PB*PC` eq(1)
As, PA is tangent to AC, `/_ACB = /_PAB`eq(2)
Given that PB=AB, So,
`/_PAB = /_APB`eq(3)
From eq(2) and eq(3),
`/_ACB = /_APB`
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