Show that the general solution of the equation dy=ylogxdx is `y=c((x)/(e))^(x)` , where c is an arbitrary constant.

What is the general solution of the differential equation x dy - y dx = y^(2)dx ? Where C is an arbitrary constant

The solution of the differential equation (dy)/(dx)=(x-y)/(x-3y) is (where, c is an arbitrary constant)

The solution of the differential equation (dy)/(dx)=(2x-y)/(x-6y) is (where c is an arbitrary constant)

The solution of the differential equation (dy)/(dx)=(x-y)/(x-3y) is (where, c is an arbitrary constant)

The solution of the differential equation (dy)/(dx)=(2x-y)/(x-6y) is (where c is an arbitrary constant)

Show that, the general solution of (1+x^(2))dy+(1+y^(2))dx=0 is x+y=c(1-xy) where c is an arbitrary constant.

The solution of the differential equation dy - (ydx)/(2x) = sqrt(x) ydy is (where , c is an arbitrary constant)

The solution of the differential equation dy - (ydx)/(2x) = sqrt(x) ydy is (where , c is an arbitrary constant)

If the general solution of a differential equation is (y+c)^2=cx , where c is an arbitrary constant then the order of the differential equation is _______.