If a radioactive substance reduces to `(1)/(16)` of its original mass in `40` days, what is its half-life ?

The activity of a radioactive element reduces to (1//16)th of its original value in 30 years. Find its half life?

The activity of a radioactive element reduces to (1//16)th of its original value in 30 years. Find its half life?

A radioactive substance reduces to 1/32 of its original value in 300 days. The half life of radioactive substance is

A radioactive substance decays to ((1)/(16))^(m) of its initial activity in 40 days. The half-life of the radioacctive substance expressed in days is

A radioactive substance decays to ((1)/(16))^(th) of its initial activity in 40 days. The half-life of the radioacctive substance expressed in days is

A radioactive substance decays to 1//16^(th) of its initial mass in 40 days. The half life of the substance, in days, is :

A radioactive substance decays to 1/32 of its initial value in 25 days. Calculate its half life.

A radioactive substance decays to 1/16 th of its initial mass in 40 days. The half life of the substance, in days, is?