In a p-n junction having depletion layer of thickness `10^(-6)` m the potential across it is `0.3 V`. Then the electric field is
Hint = `E= V/d`

In p-n junction, having depletion layer of thickness 2 ×10^(-6)m the potential difference across it is 0.2 V. The electric field is

In p-n junction, having depletion layer of thickness 2 ×10^(-6)m the potential difference across it is 0.2 V. The electric field is

In a p-n junction diode having depletion layer of thickness 10^(-6)m , the potential across it is 0.1V . The electric field produced is

In a p-n junction diode having depletion layer of thickness 10^(-6)m , the potential across it is 0.1V . The electric field produced is

In a p-n junction diode having depletion layer of thickness 10^(-6)m , the potential across it is 0.1V . The electric field produced is

In a p-n junction diode having depletion layer of thickness 10^(-6)m , the potential across it is 1V . The electric field produced is

In a p-n junction, the thickness of the depletion layer is 10^(-6) m. If the potential difference across it is 0.2 V, then the electric field set up across the junction is