For a heat engine the temperature of the source is `127^(@)C` .To have `60%` efficiency the temperature of the sink is

For an ideal heat engine, the temperature of the source is 127^(@)C . In order to have 60% efficiency the temperature of the sink should be _____ ""^(@)C . (Round off to the Nearest Integer)

In a Carnot engine the temperature of source is 1000 K and the efficiency of engine is 70%. What is the temperature of the sink ?

The efficiency of a Carnot engine is 50%. The temperature of the heat sink is 27^(@)C . Find the temperature of the heat source.

The efficiency of a Carnot engine is 50%. The temperature of the heat sink is 27^@C . Find, the temperature of the heat source.

A beat engine work on a Cannot cycle with the heat sink in the temperature of 27^(@)C . IF the efficiency is 20%, then the temperature (in Kelvin) of the heat source will be

A carnot engine has efficiency of 60%. If the source is at 527^(@)C , then find the temperature of sink.

A carnot engine has efficiency of 60%. If the source is at 527^(@)C , then find the temperature of sink.

An engine is working . It takes 100 calories of heat from source and leaves 80 calories of heat to sink . If the temperature of source is 127^(@) C, then temperature of sink is