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CrO4^(-2) (yellow) changes to Cr2O7^(2-)...

`CrO_4^(-2)` (yellow) changes to `Cr_2O_7^(2-)` (orange) in pH = x and vice - vera in pH = y Hence , x and y are

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CrO_(4)^(2-) (yellow) changes to Cr_(2)O_(7)^(2-) (orange) in pH=x and vice-versa in pH=y. Hence, x and y are:

CrO_(4)^(2-) (yellow) chages to Cr_(2)O_(7)^(2-) (orange) in p^(H) = y . Hence x and y are

CrO_(4)^(2-) (yellow) changes to Cr_(2)O_(7)^(2-)( orange ) in pH=y . Hence x and y are :

At pH = 11 , Cr_2O_7^(2-) ion changes to

At pH = 12, Cr_(2)O_(7)^(2-) changes to -

At pH=12,Cr_(2)O_(7)^(2-) changes to: