Specific volume of cylindrical virus particle is `6.02xx10^(-2) c c//g` whose radius and length `7 Å` and `10 Å` respectively. If `N_(A)=6.02xx10^(23)`, find molecular weight of virus:

Specific volume of a cylinderical virus particle is 6.02xx10^(-2)"cc"*g^(-1) whose radius and length are 7 Å & 10 Å respectively. Molecular mass (kg*mol^(-1)) of the virus-

The number of significant figures in 6.02xx10^(23) is

How many significant figures are there in 6.02xx10^23

Mass of 6.02xx10^(23) electrons is

Weight of 6.02 xx 10 ^20 molecules of H_2 is

Find the mass of. 6.02xx10^23 molecules of CO_2

The shape of Tobacco Mosaic Virus (TMC) is cylindrical, having length and diameter 3000Å and 170Å , respectively. The density of the virus is 0.08gm//ml . The molecular weight of TMC is: