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How to Proceed : In this problem there are three wires `EFAB, BE` and `BCDE`. Therefore, we have three unknown currents `i_1, i_2` and `i_3`. So, we require three equations. One equation will be obtained by applying Kirchhoff's junction law (either at `B` or at `E`) and the remainig two equations, we get from te second law (loop law). We can make three loops `ABEFA, ACDF` and `BCDEB`. But we have to chose any two of them. Initilly, we can choose any arbitrary directions of `i_1, i_2` and `i_3`.