The height at which the acceleration due to gravity becomes `g//9` in terms of R the radius of the earth is

The height at which the value of acceleration due to gravity becomes 50% of that at the surface of the earth. (radius of the earth = 6400 km ) is

The height at which the acceleration due to gravity becomes (g)/(9) (where g = the acceleration due to gravity on the surface of the Earth) in terms of R, the radius of the Earth, is:

The height at which the acceleration due to gravity becomes (g)/(9) (where g = the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth is

The height at which the acceleration due to gravity becomes g/9 (where g = acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth is .........

The height at which the acceleration due to gravity becomes (g)/(9) (where g =the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is :

The height at which the acceleration due to gravity becomes (g)/(9) (where g =the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is :

The height at which the acceleration due to gravity becomes (g)/(9) (where g =the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is :